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31103242013 is a prime number
BaseRepresentation
bin11100111101111001…
…011100111100011101
32222021122020101220102
4130331321130330131
51002144412221023
622142202230445
72150524123604
oct347571347435
988248211812
1031103242013
1112210a73098
1260404b5425
132c18b0c61c
141710b8ca3b
15c20900628
hex73de5cf1d

31103242013 has 2 divisors, whose sum is σ = 31103242014. Its totient is φ = 31103242012.

The previous prime is 31103241943. The next prime is 31103242043. The reversal of 31103242013 is 31024230113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 29976767044 + 1126474969 = 173138^2 + 33563^2 .

It is an emirp because it is prime and its reverse (31024230113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31103242013 - 210 = 31103240989 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31103242043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15551621006 + 15551621007.

It is an arithmetic number, because the mean of its divisors is an integer number (15551621007).

Almost surely, 231103242013 is an apocalyptic number.

It is an amenable number.

31103242013 is a deficient number, since it is larger than the sum of its proper divisors (1).

31103242013 is an equidigital number, since it uses as much as digits as its factorization.

31103242013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 31103242013 its reverse (31024230113), we get a palindrome (62127472126).

The spelling of 31103242013 in words is "thirty-one billion, one hundred three million, two hundred forty-two thousand, thirteen".