31104000413 has 2 divisors, whose sum is σ = 31104000414. Its totient is φ = 31104000412.

The previous prime is 31104000409. The next prime is 31104000463. The reversal of 31104000413 is 31400040113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 29483293849 + 1620706564 = 171707^2 + 40258^2 .

It is a cyclic number.

It is not a de Polignac number, because 31104000413 - 2² = 31104000409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 31104000391 and 31104000400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31104000463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15552000206 + 15552000207.

It is an arithmetic number, because the mean of its divisors is an integer number (15552000207).

Almost surely, 2^31104000413 is an apocalyptic number.

It is an amenable number.

31104000413 is a deficient number, since it is larger than the sum of its proper divisors (1).

31104000413 is an equidigital number, since it uses as much as digits as its factorization.

31104000413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 31104000413 its reverse (31400040113), we get a palindrome (62504040526).

The spelling of 31104000413 in words is "thirty-one billion, one hundred four million, four hundred thirteen", and thus it is an aban number.