Base | Representation |
---|---|
bin | 101101010001011100101… |
… | …011001000001101101110 |
3 | 102000102022200110121101202 |
4 | 231101130223020031232 |
5 | 401433023422211024 |
6 | 10341120312405502 |
7 | 440525143203344 |
oct | 55213453101556 |
9 | 12012280417352 |
10 | 3111111132014 |
11 | a9a462144806 |
12 | 422b549a6892 |
13 | 1974b82a7672 |
14 | aa8158b5994 |
15 | 55dd9170bae |
hex | 2d45cac836e |
3111111132014 has 32 divisors (see below), whose sum is σ = 4780983242880. Its totient is φ = 1517779740672.
The previous prime is 3111111132001. The next prime is 3111111132029. The reversal of 3111111132014 is 4102311111113.
3111111132014 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63784124 + ... + 63832880.
It is an arithmetic number, because the mean of its divisors is an integer number (149405726340).
Almost surely, 23111111132014 is an apocalyptic number.
3111111132014 is a deficient number, since it is larger than the sum of its proper divisors (1669872110866).
3111111132014 is a wasteful number, since it uses less digits than its factorization.
3111111132014 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52124.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 3111111132014 its reverse (4102311111113), we get a palindrome (7213422243127).
The spelling of 3111111132014 in words is "three trillion, one hundred eleven billion, one hundred eleven million, one hundred thirty-two thousand, fourteen".
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