Base | Representation |
---|---|
bin | 101101010001011101010… |
… | …000110001011001000001 |
3 | 102000102100101000221201202 |
4 | 231101131100301121001 |
5 | 401433033434000001 |
6 | 10341121304110545 |
7 | 440525323113110 |
oct | 55213520613101 |
9 | 12012311027652 |
10 | 3111121000001 |
11 | a9a467774773 |
12 | 422b58165455 |
13 | 1974ba351101 |
14 | aa816d23c77 |
15 | 55dd9e6e96b |
hex | 2d45d431641 |
3111121000001 has 4 divisors (see below), whose sum is σ = 3555566857152. Its totient is φ = 2666675142852.
The previous prime is 3111120999991. The next prime is 3111121000003. The reversal of 3111121000001 is 1000001211113.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 3111121000001 - 222 = 3111116805697 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3111121000003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222222928565 + ... + 222222928578.
It is an arithmetic number, because the mean of its divisors is an integer number (888891714288).
Almost surely, 23111121000001 is an apocalyptic number.
It is an amenable number.
3111121000001 is a deficient number, since it is larger than the sum of its proper divisors (444445857151).
3111121000001 is an equidigital number, since it uses as much as digits as its factorization.
3111121000001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 444445857150.
The product of its (nonzero) digits is 6, while the sum is 11.
Adding to 3111121000001 its reverse (1000001211113), we get a palindrome (4111122211114).
The spelling of 3111121000001 in words is "three trillion, one hundred eleven billion, one hundred twenty-one million, one", and thus it is an aban number.
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