31112103000000 has 784 divisors, whose sum is σ = 112549769344512. Its totient is φ = 7522176000000.

The previous prime is 31112102999987. The next prime is 31112103000001. The reversal of 31112103000000 is 30121113.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a self number, because there is not a number n which added to its sum of digits gives 31112103000000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31112103000001) by changing a digit.

It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 15080998969 + ... + 15081001031.

Almost surely, 2^{31112103000000} is an apocalyptic number.

31112103000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31112103000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (56274884672256).

31112103000000 is an abundant number, since it is smaller than the sum of its proper divisors (81437666344512).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31112103000000 is an equidigital number, since it uses as much as digits as its factorization.

31112103000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2576 (or 2541 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 31112103000000 its reverse (30121113), we get a palindrome (31112133121113).

The spelling of 31112103000000 in words is "thirty-one trillion, one hundred twelve billion, one hundred three million", and thus it is an aban number.