Base | Representation |
---|---|
bin | 1110001001100000011110… |
… | …11100011010110010001011 |
3 | 11002011101002121200201210100 |
4 | 13010300033130122302023 |
5 | 13034223412030401303 |
6 | 150101041011020443 |
7 | 6360561125114040 |
oct | 704601734326213 |
9 | 132141077621710 |
10 | 31113002200203 |
11 | 9a05a4a69a550 |
12 | 35a5aa959a723 |
13 | 1448c35ba97c1 |
14 | 797c3d5d31c7 |
15 | 38e4c1eb38a3 |
hex | 1c4c0f71ac8b |
31113002200203 has 48 divisors (see below), whose sum is σ = 56035041753600. Its totient is φ = 16161242739840.
The previous prime is 31113002200201. The next prime is 31113002200223. The reversal of 31113002200203 is 30200220031113.
31113002200203 is a `hidden beast` number, since 311 + 130 + 0 + 2 + 20 + 0 + 203 = 666.
It is not a de Polignac number, because 31113002200203 - 21 = 31113002200201 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31113002200201) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6410503 + ... + 10164671.
It is an arithmetic number, because the mean of its divisors is an integer number (1167396703200).
Almost surely, 231113002200203 is an apocalyptic number.
31113002200203 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
31113002200203 is a deficient number, since it is larger than the sum of its proper divisors (24922039553397).
31113002200203 is a wasteful number, since it uses less digits than its factorization.
31113002200203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3766152 (or 3766149 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 31113002200203 its reverse (30200220031113), we get a palindrome (61313222231316).
The spelling of 31113002200203 in words is "thirty-one trillion, one hundred thirteen billion, two million, two hundred thousand, two hundred three".
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