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3111303332141 is a prime number
BaseRepresentation
bin101101010001101000001…
…000010100000100101101
3102000102211002010101101222
4231101220020110010231
5401433422123112031
610341151340113125
7440532665653514
oct55215010240455
912012732111358
103111303332141
11a9a55068a594
12422ba92357a5
13197519060654
14aa83322767b
1555deae88e7b
hex2d46821412d

3111303332141 has 2 divisors, whose sum is σ = 3111303332142. Its totient is φ = 3111303332140.

The previous prime is 3111303332047. The next prime is 3111303332147. The reversal of 3111303332141 is 1412333031113.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2642689153225 + 468614178916 = 1625635^2 + 684554^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3111303332141 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3111303332141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3111303332147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1555651666070 + 1555651666071.

It is an arithmetic number, because the mean of its divisors is an integer number (1555651666071).

Almost surely, 23111303332141 is an apocalyptic number.

It is an amenable number.

3111303332141 is a deficient number, since it is larger than the sum of its proper divisors (1).

3111303332141 is an equidigital number, since it uses as much as digits as its factorization.

3111303332141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 26.

Adding to 3111303332141 its reverse (1412333031113), we get a palindrome (4523636363254).

The spelling of 3111303332141 in words is "three trillion, one hundred eleven billion, three hundred three million, three hundred thirty-two thousand, one hundred forty-one".