3111312201223 has 4 divisors (see below), whose sum is σ = 3112577479080. Its totient is φ = 3110046923368.

The previous prime is 3111312201157. The next prime is 3111312201287. The reversal of 3111312201223 is 3221022131113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3111312201223 - 2¹⁷ = 3111312070151 is a prime.

It is a super-2 number, since 2×3111312201223² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3111312201194 and 3111312201203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3111312201293) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 632635240 + ... + 632640157.

It is an arithmetic number, because the mean of its divisors is an integer number (778144369770).

Almost surely, 2^{3111312201223} is an apocalyptic number.

3111312201223 is a deficient number, since it is larger than the sum of its proper divisors (1265277857).

3111312201223 is a wasteful number, since it uses less digits than its factorization.

3111312201223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1265277856.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 3111312201223 its reverse (3221022131113), we get a palindrome (6332334332336).

The spelling of 3111312201223 in words is "three trillion, one hundred eleven billion, three hundred twelve million, two hundred one thousand, two hundred twenty-three".