Base | Representation |
---|---|
bin | 1001000011100001101… |
… | …11101110010011011001 |
3 | 1002202002021102201012112 |
4 | 10201300313232103121 |
5 | 20044144103113311 |
6 | 354533131322105 |
7 | 31323060265226 |
oct | 4416067562331 |
9 | 1082067381175 |
10 | 311131301081 |
11 | 10aa4a565587 |
12 | 503712b0335 |
13 | 23455008cb3 |
14 | 110b763094d |
15 | 815ea3728b |
hex | 4870dee4d9 |
311131301081 has 2 divisors, whose sum is σ = 311131301082. Its totient is φ = 311131301080.
The previous prime is 311131301059. The next prime is 311131301087. The reversal of 311131301081 is 180103131113.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 277640471056 + 33490830025 = 526916^2 + 183005^2 .
It is a cyclic number.
It is not a de Polignac number, because 311131301081 - 230 = 310057559257 is a prime.
It is a super-2 number, since 2×3111313010812 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (311131301087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155565650540 + 155565650541.
It is an arithmetic number, because the mean of its divisors is an integer number (155565650541).
Almost surely, 2311131301081 is an apocalyptic number.
It is an amenable number.
311131301081 is a deficient number, since it is larger than the sum of its proper divisors (1).
311131301081 is an equidigital number, since it uses as much as digits as its factorization.
311131301081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 23.
Adding to 311131301081 its reverse (180103131113), we get a palindrome (491234432194).
The spelling of 311131301081 in words is "three hundred eleven billion, one hundred thirty-one million, three hundred one thousand, eighty-one".
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