Base | Representation |
---|---|
bin | 1110001001100000101110… |
… | …01000001101100111010111 |
3 | 11002011101102121021121000210 |
4 | 13010300113020031213113 |
5 | 13034224143031333421 |
6 | 150101101454140503 |
7 | 6360564251661534 |
oct | 704602710154727 |
9 | 132141377247023 |
10 | 31113131121111 |
11 | 9a06006444756 |
12 | 35a5b247b1733 |
13 | 1448c56808070 |
14 | 797c52791d8b |
15 | 38e4cd47c576 |
hex | 1c4c1720d9d7 |
31113131121111 has 8 divisors (see below), whose sum is σ = 44675265199600. Its totient is φ = 19146542228352.
The previous prime is 31113131121089. The next prime is 31113131121161. The reversal of 31113131121111 is 11112113131113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 31113131121111 - 221 = 31113129023959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31113131121161) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 398886296386 + ... + 398886296463.
It is an arithmetic number, because the mean of its divisors is an integer number (5584408149950).
Almost surely, 231113131121111 is an apocalyptic number.
31113131121111 is a deficient number, since it is larger than the sum of its proper divisors (13562134078489).
31113131121111 is a wasteful number, since it uses less digits than its factorization.
31113131121111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 797772592865.
The product of its digits is 54, while the sum is 21.
Adding to 31113131121111 its reverse (11112113131113), we get a palindrome (42225244252224).
The spelling of 31113131121111 in words is "thirty-one trillion, one hundred thirteen billion, one hundred thirty-one million, one hundred twenty-one thousand, one hundred eleven".
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