Base | Representation |
---|---|
bin | 1001000011100001110… |
… | …11100111000100001101 |
3 | 1002202002100100110220202 |
4 | 10201300323213010031 |
5 | 20044144333220023 |
6 | 354533205223245 |
7 | 31323102040664 |
oct | 4416073470415 |
9 | 1082070313822 |
10 | 311132320013 |
11 | 10aa500a1079 |
12 | 50371701b25 |
13 | 234552a4a08 |
14 | 110b7817ddb |
15 | 815eb89128 |
hex | 4870ee710d |
311132320013 has 2 divisors, whose sum is σ = 311132320014. Its totient is φ = 311132320012.
The previous prime is 311132319973. The next prime is 311132320061. The reversal of 311132320013 is 310023231113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 274673472649 + 36458847364 = 524093^2 + 190942^2 .
It is an emirp because it is prime and its reverse (310023231113) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-311132320013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311132320813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155566160006 + 155566160007.
It is an arithmetic number, because the mean of its divisors is an integer number (155566160007).
Almost surely, 2311132320013 is an apocalyptic number.
It is an amenable number.
311132320013 is a deficient number, since it is larger than the sum of its proper divisors (1).
311132320013 is an equidigital number, since it uses as much as digits as its factorization.
311132320013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 311132320013 its reverse (310023231113), we get a palindrome (621155551126).
The spelling of 311132320013 in words is "three hundred eleven billion, one hundred thirty-two million, three hundred twenty thousand, thirteen".
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