Base | Representation |
---|---|
bin | 1110001001100001000010… |
… | …10101010010010000000010 |
3 | 11002011101212112102101221012 |
4 | 13010300201111102100002 |
5 | 13034230020343221010 |
6 | 150101130451400522 |
7 | 6360601431103202 |
oct | 704604125222002 |
9 | 132141775371835 |
10 | 31113302320130 |
11 | 9a06094046048 |
12 | 35a5b71bb3142 |
13 | 1448c8311a064 |
14 | 797c6b3d8402 |
15 | 38e4dd4e8005 |
hex | 1c4c21552402 |
31113302320130 has 8 divisors (see below), whose sum is σ = 56003944176252. Its totient is φ = 12445320928048.
The previous prime is 31113302320129. The next prime is 31113302320151. The reversal of 31113302320130 is 3102320331113.
It can be written as a sum of positive squares in 2 ways, for example, as 30747723673969 + 365578646161 = 5545063^2 + 604631^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 31113302320096 and 31113302320105.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1555665115997 + ... + 1555665116016.
Almost surely, 231113302320130 is an apocalyptic number.
31113302320130 is a deficient number, since it is larger than the sum of its proper divisors (24890641856122).
31113302320130 is a wasteful number, since it uses less digits than its factorization.
31113302320130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3111330232020.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 31113302320130 its reverse (3102320331113), we get a palindrome (34215622651243).
The spelling of 31113302320130 in words is "thirty-one trillion, one hundred thirteen billion, three hundred two million, three hundred twenty thousand, one hundred thirty".
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