Base | Representation |
---|---|
bin | 1110001001100001000100… |
… | …11001011111011101011111 |
3 | 11002011101220210001210112202 |
4 | 13010300202121133131133 |
5 | 13034230034432400111 |
6 | 150101132330522115 |
7 | 6360602036062166 |
oct | 704604231373537 |
9 | 132141823053482 |
10 | 31113320200031 |
11 | 9a060a3148523 |
12 | 35a5b77b9633b |
13 | 1448c86a3a494 |
14 | 797c6d9303dd |
15 | 38e4ded7ab3b |
hex | 1c4c2265f75f |
31113320200031 has 2 divisors, whose sum is σ = 31113320200032. Its totient is φ = 31113320200030.
The previous prime is 31113320200003. The next prime is 31113320200093. The reversal of 31113320200031 is 13000202331113.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31113320200031 - 234 = 31096140330847 is a prime.
It is a super-2 number, since 2×311133202000312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31113320199976 and 31113320200012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31113320200231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15556660100015 + 15556660100016.
It is an arithmetic number, because the mean of its divisors is an integer number (15556660100016).
Almost surely, 231113320200031 is an apocalyptic number.
31113320200031 is a deficient number, since it is larger than the sum of its proper divisors (1).
31113320200031 is an equidigital number, since it uses as much as digits as its factorization.
31113320200031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 31113320200031 its reverse (13000202331113), we get a palindrome (44113522531144).
The spelling of 31113320200031 in words is "thirty-one trillion, one hundred thirteen billion, three hundred twenty million, two hundred thousand, thirty-one".
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