Base | Representation |
---|---|
bin | 11100111110100011… |
… | …101011011101111001 |
3 | 2222022102001210110002 |
4 | 130332203223131321 |
5 | 1002210230432140 |
6 | 22143235402345 |
7 | 2151020166362 |
oct | 347643533571 |
9 | 88272053402 |
10 | 31114311545 |
11 | 12217243869 |
12 | 60441533b5 |
13 | 2c1b1b6c45 |
14 | 1712430b69 |
15 | c2188a415 |
hex | 73e8eb779 |
31114311545 has 4 divisors (see below), whose sum is σ = 37337173860. Its totient is φ = 24891449232.
The previous prime is 31114311499. The next prime is 31114311577. The reversal of 31114311545 is 54511341113.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 12133463104 + 18980848441 = 110152^2 + 137771^2 .
It is a cyclic number.
It is not a de Polignac number, because 31114311545 - 224 = 31097534329 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3111431150 + ... + 3111431159.
It is an arithmetic number, because the mean of its divisors is an integer number (9334293465).
Almost surely, 231114311545 is an apocalyptic number.
It is an amenable number.
31114311545 is a deficient number, since it is larger than the sum of its proper divisors (6222862315).
31114311545 is an equidigital number, since it uses as much as digits as its factorization.
31114311545 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6222862314.
The product of its digits is 3600, while the sum is 29.
Adding to 31114311545 its reverse (54511341113), we get a palindrome (85625652658).
The spelling of 31114311545 in words is "thirty-one billion, one hundred fourteen million, three hundred eleven thousand, five hundred forty-five".
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