Base | Representation |
---|---|
bin | 11100111110100011… |
… | …101101100100001111 |
3 | 2222022102002020020112 |
4 | 130332203231210033 |
5 | 1002210231221033 |
6 | 22143235510235 |
7 | 2151020233424 |
oct | 347643554417 |
9 | 88272066215 |
10 | 31114320143 |
11 | 1221724a275 |
12 | 604415837b |
13 | 2c1b1bab2a |
14 | 1712433d4b |
15 | c2188cc48 |
hex | 73e8ed90f |
31114320143 has 4 divisors (see below), whose sum is σ = 32751915960. Its totient is φ = 29476724328.
The previous prime is 31114320119. The next prime is 31114320179. The reversal of 31114320143 is 34102341113.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34102341113 = 29 ⋅1175942797.
It is a cyclic number.
It is not a de Polignac number, because 31114320143 - 228 = 30845884687 is a prime.
It is a super-2 number, since 2×311143201432 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31114320113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 818797880 + ... + 818797917.
It is an arithmetic number, because the mean of its divisors is an integer number (8187978990).
Almost surely, 231114320143 is an apocalyptic number.
31114320143 is a deficient number, since it is larger than the sum of its proper divisors (1637595817).
31114320143 is a wasteful number, since it uses less digits than its factorization.
31114320143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1637595816.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 31114320143 its reverse (34102341113), we get a palindrome (65216661256).
The spelling of 31114320143 in words is "thirty-one billion, one hundred fourteen million, three hundred twenty thousand, one hundred forty-three".
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