Base | Representation |
---|---|
bin | 1001000011100011001… |
… | …01001111011110001111 |
3 | 1002202010002212221022010 |
4 | 10201301211033132033 |
5 | 20044210131432143 |
6 | 354534235152303 |
7 | 31323263563341 |
oct | 4416145173617 |
9 | 1082102787263 |
10 | 311143233423 |
11 | 10aa56275520 |
12 | 503752a5693 |
13 | 23457626259 |
14 | 110b9059291 |
15 | 8160ae2a33 |
hex | 487194f78f |
311143233423 has 32 divisors (see below), whose sum is σ = 465774888960. Its totient is φ = 183091743360.
The previous prime is 311143233403. The next prime is 311143233437. The reversal of 311143233423 is 324332341113.
It is not a de Polignac number, because 311143233423 - 217 = 311143102351 is a prime.
It is a super-2 number, since 2×3111432334232 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311143233403) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 318861 + ... + 850857.
It is an arithmetic number, because the mean of its divisors is an integer number (14555465280).
Almost surely, 2311143233423 is an apocalyptic number.
311143233423 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
311143233423 is a deficient number, since it is larger than the sum of its proper divisors (154631655537).
311143233423 is a wasteful number, since it uses less digits than its factorization.
311143233423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 532527.
The product of its digits is 15552, while the sum is 30.
Adding to 311143233423 its reverse (324332341113), we get a palindrome (635475574536).
The spelling of 311143233423 in words is "three hundred eleven billion, one hundred forty-three million, two hundred thirty-three thousand, four hundred twenty-three".
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