311143413031 has 4 divisors (see below), whose sum is σ = 339429177864. Its totient is φ = 282857648200.

The previous prime is 311143413013. The next prime is 311143413037. The reversal of 311143413031 is 130314341113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 311143413031 - 2¹¹ = 311143410983 is a prime.

It is a super-2 number, since 2×311143413031² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 311143412987 and 311143413005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311143413037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14142882400 + ... + 14142882421.

It is an arithmetic number, because the mean of its divisors is an integer number (84857294466).

Almost surely, 2^311143413031 is an apocalyptic number.

311143413031 is a deficient number, since it is larger than the sum of its proper divisors (28285764833).

311143413031 is a wasteful number, since it uses less digits than its factorization.

311143413031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28285764832.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 311143413031 its reverse (130314341113), we get a palindrome (441457754144).

The spelling of 311143413031 in words is "three hundred eleven billion, one hundred forty-three million, four hundred thirteen thousand, thirty-one".