Base | Representation |
---|---|
bin | 1110001001100100100111… |
… | …10010010100000011110101 |
3 | 11002011120211100122021212222 |
4 | 13010302103302110003311 |
5 | 13034242433432013331 |
6 | 150102045204252125 |
7 | 6361000135454423 |
oct | 704622362240365 |
9 | 132146740567788 |
10 | 31115222532341 |
11 | 9a06989a46992 |
12 | 35a64090a1045 |
13 | 14491caba97bc |
14 | 797db0444113 |
15 | 38e5a1d99b7b |
hex | 1c4c93c940f5 |
31115222532341 has 2 divisors, whose sum is σ = 31115222532342. Its totient is φ = 31115222532340.
The previous prime is 31115222532271. The next prime is 31115222532343. The reversal of 31115222532341 is 14323522251113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23863996836241 + 7251225696100 = 4885079^2 + 2692810^2 .
It is a cyclic number.
It is not a de Polignac number, because 31115222532341 - 234 = 31098042663157 is a prime.
Together with 31115222532343, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31115222532343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15557611266170 + 15557611266171.
It is an arithmetic number, because the mean of its divisors is an integer number (15557611266171).
Almost surely, 231115222532341 is an apocalyptic number.
It is an amenable number.
31115222532341 is a deficient number, since it is larger than the sum of its proper divisors (1).
31115222532341 is an equidigital number, since it uses as much as digits as its factorization.
31115222532341 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 43200, while the sum is 35.
Adding to 31115222532341 its reverse (14323522251113), we get a palindrome (45438744783454).
The spelling of 31115222532341 in words is "thirty-one trillion, one hundred fifteen billion, two hundred twenty-two million, five hundred thirty-two thousand, three hundred forty-one".
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