311152505133 has 4 divisors (see below), whose sum is σ = 414870006848. Its totient is φ = 207435003420.

The previous prime is 311152505123. The next prime is 311152505137. The reversal of 311152505133 is 331505251113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 311152505133 - 2²⁰ = 311151456557 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 311152505133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311152505137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51858750853 + ... + 51858750858.

It is an arithmetic number, because the mean of its divisors is an integer number (103717501712).

Almost surely, 2^311152505133 is an apocalyptic number.

It is an amenable number.

311152505133 is a deficient number, since it is larger than the sum of its proper divisors (103717501715).

311152505133 is a wasteful number, since it uses less digits than its factorization.

311152505133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103717501714.

The product of its (nonzero) digits is 6750, while the sum is 30.

Adding to 311152505133 its reverse (331505251113), we get a palindrome (642657756246).

The spelling of 311152505133 in words is "three hundred eleven billion, one hundred fifty-two million, five hundred five thousand, one hundred thirty-three".