Base | Representation |
---|---|
bin | 100011011000010010010100… |
… | …0110111100100110000111101 |
3 | 1111210212112111220002220010021 |
4 | 1012300210220313210300331 |
5 | 311242204404020222141 |
6 | 3021511454223412141 |
7 | 122356353064313662 |
oct | 10660445067446075 |
9 | 1453775456086107 |
10 | 311201131023421 |
11 | 90181727514231 |
12 | 2aaa0a45154051 |
13 | 104851aa26b762 |
14 | 56bc302385a69 |
15 | 25ea0c79006d1 |
hex | 11b0928de4c3d |
311201131023421 has 4 divisors (see below), whose sum is σ = 311201646215200. Its totient is φ = 311200615831644.
The previous prime is 311201131023403. The next prime is 311201131023473. The reversal of 311201131023421 is 124320131102113.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 311201131023421 - 215 = 311201130990653 is a prime.
It is a super-2 number, since 2×3112011310234212 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311201131023521) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 256688751 + ... + 257898268.
It is an arithmetic number, because the mean of its divisors is an integer number (77800411553800).
Almost surely, 2311201131023421 is an apocalyptic number.
It is an amenable number.
311201131023421 is a deficient number, since it is larger than the sum of its proper divisors (515191779).
311201131023421 is an equidigital number, since it uses as much as digits as its factorization.
311201131023421 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 515191778.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 311201131023421 its reverse (124320131102113), we get a palindrome (435521262125534).
The spelling of 311201131023421 in words is "three hundred eleven trillion, two hundred one billion, one hundred thirty-one million, twenty-three thousand, four hundred twenty-one".
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