Base | Representation |
---|---|
bin | 1110001001101101111011… |
… | …10010001110100001000011 |
3 | 11002012001201210020122211101 |
4 | 13010312331302032201003 |
5 | 13034333203330320003 |
6 | 150104233242555231 |
7 | 6361235054323642 |
oct | 704667562164103 |
9 | 132161653218741 |
10 | 31120222120003 |
11 | 9a090150a2115 |
12 | 35a7383508b17 |
13 | 14498169227b3 |
14 | 798326439359 |
15 | 38e795c6e11d |
hex | 1c4dbdc8e843 |
31120222120003 has 4 divisors (see below), whose sum is σ = 31127525626288. Its totient is φ = 31112918613720.
The previous prime is 31120222119991. The next prime is 31120222120061. The reversal of 31120222120003 is 30002122202113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31120222120003 - 25 = 31120222119971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31120222120073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3651746751 + ... + 3651755272.
It is an arithmetic number, because the mean of its divisors is an integer number (7781881406572).
Almost surely, 231120222120003 is an apocalyptic number.
31120222120003 is a deficient number, since it is larger than the sum of its proper divisors (7303506285).
31120222120003 is an equidigital number, since it uses as much as digits as its factorization.
31120222120003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7303506284.
The product of its (nonzero) digits is 288, while the sum is 19.
Adding to 31120222120003 its reverse (30002122202113), we get a palindrome (61122344322116).
The spelling of 31120222120003 in words is "thirty-one trillion, one hundred twenty billion, two hundred twenty-two million, one hundred twenty thousand, three".
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