3112103230133 has 4 divisors (see below), whose sum is σ = 3112380143520. Its totient is φ = 3111826316748.

The previous prime is 3112103230091. The next prime is 3112103230141. The reversal of 3112103230133 is 3310323012113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3112103230133 - 2²⁰ = 3112102181557 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 3112103230099 and 3112103230108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3112103230193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 138439835 + ... + 138462312.

It is an arithmetic number, because the mean of its divisors is an integer number (778095035880).

Almost surely, 2^{3112103230133} is an apocalyptic number.

It is an amenable number.

3112103230133 is a deficient number, since it is larger than the sum of its proper divisors (276913387).

3112103230133 is a wasteful number, since it uses less digits than its factorization.

3112103230133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 276913386.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 3112103230133 its reverse (3310323012113), we get a palindrome (6422426242246).

The spelling of 3112103230133 in words is "three trillion, one hundred twelve billion, one hundred three million, two hundred thirty thousand, one hundred thirty-three".