Base | Representation |
---|---|
bin | 11100111110111101… |
… | …100101000011100111 |
3 | 2222022212211201212112 |
4 | 130332331211003213 |
5 | 1002214000213111 |
6 | 22144041111235 |
7 | 2151131664656 |
oct | 347675450347 |
9 | 88285751775 |
10 | 31121101031 |
11 | 12220060909 |
12 | 604648851b |
13 | 2c1c7233a7 |
14 | 17132bb19d |
15 | c2227be8b |
hex | 73ef650e7 |
31121101031 has 2 divisors, whose sum is σ = 31121101032. Its totient is φ = 31121101030.
The previous prime is 31121101019. The next prime is 31121101079. The reversal of 31121101031 is 13010112113.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (13010112113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 31121101031 - 214 = 31121084647 is a prime.
It is a super-2 number, since 2×311211010312 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 31121100997 and 31121101015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (31121101331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15560550515 + 15560550516.
It is an arithmetic number, because the mean of its divisors is an integer number (15560550516).
Almost surely, 231121101031 is an apocalyptic number.
31121101031 is a deficient number, since it is larger than the sum of its proper divisors (1).
31121101031 is an equidigital number, since it uses as much as digits as its factorization.
31121101031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 31121101031 its reverse (13010112113), we get a palindrome (44131213144).
The spelling of 31121101031 in words is "thirty-one billion, one hundred twenty-one million, one hundred one thousand, thirty-one".
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