Base | Representation |
---|---|
bin | 1110001001101111100101… |
… | …01101010010111110011111 |
3 | 11002012011000122222122122102 |
4 | 13010313302231102332133 |
5 | 13034342013131114444 |
6 | 150104501321435315 |
7 | 6361266055335446 |
oct | 704676255227637 |
9 | 132164018878572 |
10 | 31121110019999 |
11 | 9a0943030a56a |
12 | 35a759093bb3b |
13 | 14499288707cc |
14 | 7983ac325d5d |
15 | 38e7e8baa84e |
hex | 1c4df2b52f9f |
31121110019999 has 4 divisors (see below), whose sum is σ = 31121683534440. Its totient is φ = 31120536505560.
The previous prime is 31121110019957. The next prime is 31121110020029. The reversal of 31121110019999 is 99991001112113.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31121110019999 - 240 = 30021598392223 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31121110010999) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 286675817 + ... + 286784354.
It is an arithmetic number, because the mean of its divisors is an integer number (7780420883610).
Almost surely, 231121110019999 is an apocalyptic number.
31121110019999 is a deficient number, since it is larger than the sum of its proper divisors (573514441).
31121110019999 is an equidigital number, since it uses as much as digits as its factorization.
31121110019999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 573514440.
The product of its (nonzero) digits is 39366, while the sum is 47.
The spelling of 31121110019999 in words is "thirty-one trillion, one hundred twenty-one billion, one hundred ten million, nineteen thousand, nine hundred ninety-nine".
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