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31121110020000 = 25354711132231733
BaseRepresentation
bin1110001001101111100101…
…01101010010111110100000
311002012011000122222122122110
413010313302231102332200
513034342013131120000
6150104501321435320
76361266055335450
oct704676255227640
9132164018878573
1031121110020000
119a0943030a570
1235a759093bb40
131449928870800
147983ac325d60
1538e7e8baa850
hex1c4df2b52fa0

31121110020000 has 2880 divisors, whose sum is σ = 143891199277056. Its totient is φ = 5706455040000.

The previous prime is 31121110019957. The next prime is 31121110020029. The reversal of 31121110020000 is 2001112113.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 479 ways as a sum of consecutive naturals, for example, 17957939134 + ... + 17957940866.

Almost surely, 231121110020000 is an apocalyptic number.

31121110020000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 31121110020000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (71945599638528).

31121110020000 is an abundant number, since it is smaller than the sum of its proper divisors (112770089257056).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

31121110020000 is a wasteful number, since it uses less digits than its factorization.

31121110020000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1833 (or 1797 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 12.

Adding to 31121110020000 its reverse (2001112113), we get a palindrome (31123111132113).

The spelling of 31121110020000 in words is "thirty-one trillion, one hundred twenty-one billion, one hundred ten million, twenty thousand".