3112111140101 has 4 divisors (see below), whose sum is σ = 3112115152992. Its totient is φ = 3112107127212.

The previous prime is 3112111140079. The next prime is 3112111140107. The reversal of 3112111140101 is 1010411112113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3112111140101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 3112111140101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3112111140107) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 430601 + ... + 2531726.

It is an arithmetic number, because the mean of its divisors is an integer number (778028788248).

Almost surely, 2^{3112111140101} is an apocalyptic number.

It is an amenable number.

3112111140101 is a deficient number, since it is larger than the sum of its proper divisors (4012891).

3112111140101 is a wasteful number, since it uses less digits than its factorization.

3112111140101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4012890.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 3112111140101 its reverse (1010411112113), we get a palindrome (4122522252214).

The spelling of 3112111140101 in words is "three trillion, one hundred twelve billion, one hundred eleven million, one hundred forty thousand, one hundred one".