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311212113001 = 632474920583
BaseRepresentation
bin1001000011101011010…
…11111111110001101001
31002202021220111101022121
410201311223333301221
520044330300104001
6354545135351241
731325061212416
oct4416553776151
91082256441277
10311212113001
1110aa91140799
1250394382521
1323468991aba
14110c426910d
158166b9b6a1
hex4875affc69

311212113001 has 4 divisors (see below), whose sum is σ = 311217096832. Its totient is φ = 311207129172.

The previous prime is 311212112971. The next prime is 311212113019. The reversal of 311212113001 is 100311212113.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 311212113001 - 25 = 311212112969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (311212113601) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2397045 + ... + 2523538.

It is an arithmetic number, because the mean of its divisors is an integer number (77804274208).

Almost surely, 2311212113001 is an apocalyptic number.

It is an amenable number.

311212113001 is a deficient number, since it is larger than the sum of its proper divisors (4983831).

311212113001 is an equidigital number, since it uses as much as digits as its factorization.

311212113001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4983830.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 311212113001 its reverse (100311212113), we get a palindrome (411523325114).

The spelling of 311212113001 in words is "three hundred eleven billion, two hundred twelve million, one hundred thirteen thousand, one".

Divisors: 1 63247 4920583 311212113001