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3112144877437 = 3911795741467
BaseRepresentation
bin101101010010011010010…
…010100011011101111101
3102000111222201122022112021
4231102122102203131331
5401442133042034222
610341411041240141
7440562564662401
oct55223222433575
912014881568467
103112144877437
11a9a942716a72
124231a3033051
131976214cb54b
14aa8b2cc9101
1555e49cbaac7
hex2d49a4a377d

3112144877437 has 4 divisors (see below), whose sum is σ = 3112940622816. Its totient is φ = 3111349132060.

The previous prime is 3112144877407. The next prime is 3112144877441. The reversal of 3112144877437 is 7347784412113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3112144877437 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3112144877407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 397866823 + ... + 397874644.

It is an arithmetic number, because the mean of its divisors is an integer number (778235155704).

Almost surely, 23112144877437 is an apocalyptic number.

It is an amenable number.

3112144877437 is a deficient number, since it is larger than the sum of its proper divisors (795745379).

3112144877437 is an equidigital number, since it uses as much as digits as its factorization.

3112144877437 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 795745378.

The product of its digits is 3161088, while the sum is 52.

The spelling of 3112144877437 in words is "three trillion, one hundred twelve billion, one hundred forty-four million, eight hundred seventy-seven thousand, four hundred thirty-seven".

Divisors: 1 3911 795741467 3112144877437