311221300001 has 2 divisors, whose sum is σ = 311221300002. Its totient is φ = 311221300000.

The previous prime is 311221299929. The next prime is 311221300003. The reversal of 311221300001 is 100003122113.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 231191718976 + 80029581025 = 480824^2 + 282895^2 .

It is a cyclic number.

It is not a de Polignac number, because 311221300001 - 2³⁰ = 310147558177 is a prime.

Together with 311221300003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (311221300003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155610650000 + 155610650001.

It is an arithmetic number, because the mean of its divisors is an integer number (155610650001).

Almost surely, 2^311221300001 is an apocalyptic number.

It is an amenable number.

311221300001 is a deficient number, since it is larger than the sum of its proper divisors (1).

311221300001 is an equidigital number, since it uses as much as digits as its factorization.

311221300001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 311221300001 its reverse (100003122113), we get a palindrome (411224422114).

The spelling of 311221300001 in words is "three hundred eleven billion, two hundred twenty-one million, three hundred thousand, one".