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31122431143 = 97553319031
BaseRepresentation
bin11100111111000010…
…101001110010100111
32222022222100022102221
4130333002221302213
51002214320244033
622144125413211
72151146204566
oct347702516247
988288308387
1031122431143
111222088a181
126046a0a207
132c1ca9a93b
141713545bdd
15c2244112d
hex73f0a9ca7

31122431143 has 4 divisors (see below), whose sum is σ = 31122847728. Its totient is φ = 31122014560.

The previous prime is 31122431141. The next prime is 31122431161. The reversal of 31122431143 is 34113422113.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34113422113 = 172006671889.

It is a cyclic number.

It is not a de Polignac number, because 31122431143 - 21 = 31122431141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31122431141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61963 + ... + 257068.

It is an arithmetic number, because the mean of its divisors is an integer number (7780711932).

Almost surely, 231122431143 is an apocalyptic number.

31122431143 is a deficient number, since it is larger than the sum of its proper divisors (416585).

31122431143 is an equidigital number, since it uses as much as digits as its factorization.

31122431143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 416584.

The product of its digits is 1728, while the sum is 25.

Adding to 31122431143 its reverse (34113422113), we get a palindrome (65235853256).

The spelling of 31122431143 in words is "thirty-one billion, one hundred twenty-two million, four hundred thirty-one thousand, one hundred forty-three".

Divisors: 1 97553 319031 31122431143