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3112325149 is a prime number
BaseRepresentation
bin1011100110000010…
…0101000000011101
322000220101111110211
42321200211000131
522333223401044
61232455532421
7140061220153
oct27140450035
98026344424
103112325149
11135790aa4a
1272a38a111
133a7a5201b
142174c53d3
15133380634
hexb982501d

3112325149 has 2 divisors, whose sum is σ = 3112325150. Its totient is φ = 3112325148.

The previous prime is 3112325131. The next prime is 3112325179. The reversal of 3112325149 is 9415232113.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2994059524 + 118265625 = 54718^2 + 10875^2 .

It is a cyclic number.

It is not a de Polignac number, because 3112325149 - 217 = 3112194077 is a prime.

It is a super-3 number, since 3×31123251493 (a number of 29 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 3112325149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3112325179) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556162574 + 1556162575.

It is an arithmetic number, because the mean of its divisors is an integer number (1556162575).

Almost surely, 23112325149 is an apocalyptic number.

It is an amenable number.

3112325149 is a deficient number, since it is larger than the sum of its proper divisors (1).

3112325149 is an equidigital number, since it uses as much as digits as its factorization.

3112325149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6480, while the sum is 31.

The square root of 3112325149 is about 55788.2169369124. The cubic root of 3112325149 is about 1460.0295779646.

The spelling of 3112325149 in words is "three billion, one hundred twelve million, three hundred twenty-five thousand, one hundred forty-nine".