Base | Representation |
---|---|
bin | 1001000011101110101… |
… | …10111000011011110101 |
3 | 1002202100212012220121221 |
4 | 10201313112320123311 |
5 | 20044404433213331 |
6 | 354552020110341 |
7 | 31325551321435 |
oct | 4416726703365 |
9 | 1082325186557 |
10 | 311240132341 |
11 | 10aaa5a39076 |
12 | 503a18353b1 |
13 | 234717223a8 |
14 | 110c7c802c5 |
15 | 8169383711 |
hex | 48775b86f5 |
311240132341 has 8 divisors (see below), whose sum is σ = 324788641344. Its totient is φ = 297692984160.
The previous prime is 311240132317. The next prime is 311240132407. The reversal of 311240132341 is 143231042113.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 311240132341 - 223 = 311231743733 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311240132941) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 141721 + ... + 801601.
It is an arithmetic number, because the mean of its divisors is an integer number (40598580168).
Almost surely, 2311240132341 is an apocalyptic number.
It is an amenable number.
311240132341 is a deficient number, since it is larger than the sum of its proper divisors (13548509003).
311240132341 is a wasteful number, since it uses less digits than its factorization.
311240132341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 680411.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 311240132341 its reverse (143231042113), we get a palindrome (454471174454).
The spelling of 311240132341 in words is "three hundred eleven billion, two hundred forty million, one hundred thirty-two thousand, three hundred forty-one".
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