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311240132341 = 2320507659881
BaseRepresentation
bin1001000011101110101…
…10111000011011110101
31002202100212012220121221
410201313112320123311
520044404433213331
6354552020110341
731325551321435
oct4416726703365
91082325186557
10311240132341
1110aaa5a39076
12503a18353b1
13234717223a8
14110c7c802c5
158169383711
hex48775b86f5

311240132341 has 8 divisors (see below), whose sum is σ = 324788641344. Its totient is φ = 297692984160.

The previous prime is 311240132317. The next prime is 311240132407. The reversal of 311240132341 is 143231042113.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 311240132341 - 223 = 311231743733 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (311240132941) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 141721 + ... + 801601.

It is an arithmetic number, because the mean of its divisors is an integer number (40598580168).

Almost surely, 2311240132341 is an apocalyptic number.

It is an amenable number.

311240132341 is a deficient number, since it is larger than the sum of its proper divisors (13548509003).

311240132341 is a wasteful number, since it uses less digits than its factorization.

311240132341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 680411.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 311240132341 its reverse (143231042113), we get a palindrome (454471174454).

The spelling of 311240132341 in words is "three hundred eleven billion, two hundred forty million, one hundred thirty-two thousand, three hundred forty-one".

Divisors: 1 23 20507 471661 659881 15177263 13532179667 311240132341