3112402413101 has 4 divisors (see below), whose sum is σ = 3113302735452. Its totient is φ = 3111502090752.

The previous prime is 3112402413097. The next prime is 3112402413103. The reversal of 3112402413101 is 1013142042113.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 936036900100 + 2176365513001 = 967490^2 + 1475251^2 .

It is a cyclic number.

It is not a de Polignac number, because 3112402413101 - 2² = 3112402413097 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3112402413103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 450155990 + ... + 450162903.

It is an arithmetic number, because the mean of its divisors is an integer number (778325683863).

Almost surely, 2^{3112402413101} is an apocalyptic number.

It is an amenable number.

3112402413101 is a deficient number, since it is larger than the sum of its proper divisors (900322351).

3112402413101 is an equidigital number, since it uses as much as digits as its factorization.

3112402413101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 900322350.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 3112402413101 its reverse (1013142042113), we get a palindrome (4125544455214).

The spelling of 3112402413101 in words is "three trillion, one hundred twelve billion, four hundred two million, four hundred thirteen thousand, one hundred one".