311241140130 has 64 divisors (see below), whose sum is σ = 757643673600. Its totient is φ = 81813090240.

The previous prime is 311241140081. The next prime is 311241140167. The reversal of 311241140130 is 31041142113.

It is a junction number, because it is equal to n+sod(n) for n = 311241140097 and 311241140106.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 14982691 + ... + 15003449.

It is an arithmetic number, because the mean of its divisors is an integer number (11838182400).

Almost surely, 2^311241140130 is an apocalyptic number.

311241140130 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

311241140130 is an abundant number, since it is smaller than the sum of its proper divisors (446402533470).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

311241140130 is a wasteful number, since it uses less digits than its factorization.

311241140130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27879.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 311241140130 its reverse (31041142113), we get a palindrome (342282282243).

The spelling of 311241140130 in words is "three hundred eleven billion, two hundred forty-one million, one hundred forty thousand, one hundred thirty".