3113001300020 has 48 divisors (see below), whose sum is σ = 6590396252160. Its totient is φ = 1235092287744.

The previous prime is 3113001300001. The next prime is 3113001300029. The reversal of 3113001300020 is 200031003113.

It is a junction number, because it is equal to n+sod(n) for n = 3113001299968 and 3113001300004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3113001300029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10334096 + ... + 10631064.

It is an arithmetic number, because the mean of its divisors is an integer number (137299921920).

Almost surely, 2^{3113001300020} is an apocalyptic number.

It is an amenable number.

3113001300020 is an abundant number, since it is smaller than the sum of its proper divisors (3477394952140).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3113001300020 is a wasteful number, since it uses less digits than its factorization.

3113001300020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 301232 (or 301230 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 3113001300020 its reverse (200031003113), we get a palindrome (3313032303133).

The spelling of 3113001300020 in words is "three trillion, one hundred thirteen billion, one million, three hundred thousand, twenty".