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31130044513 = 172107716417
BaseRepresentation
bin11100111111011111…
…101100100001100001
32222100111200010000121
4130333133230201201
51002223242411023
622145000520241
72151301004161
oct347737544141
988314603017
1031130044513
111222510a217
126049480081
132c215350a9
1417145685a1
15c22e46d5d
hex73f7ec861

31130044513 has 6 divisors (see below), whose sum is σ = 33068940326. Its totient is φ = 29298865152.

The previous prime is 31130044493. The next prime is 31130044529. The reversal of 31130044513 is 31544003113.

It can be written as a sum of positive squares in 3 ways, for example, as 7735730209 + 23394314304 = 87953^2 + 152952^2 .

It is not a de Polignac number, because 31130044513 - 25 = 31130044481 is a prime.

It is a super-2 number, since 2×311300445132 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (31130044573) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 53857920 + ... + 53858497.

Almost surely, 231130044513 is an apocalyptic number.

It is an amenable number.

31130044513 is a deficient number, since it is larger than the sum of its proper divisors (1938895813).

31130044513 is a wasteful number, since it uses less digits than its factorization.

31130044513 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107716451 (or 107716434 counting only the distinct ones).

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 31130044513 its reverse (31544003113), we get a palindrome (62674047626).

The spelling of 31130044513 in words is "thirty-one billion, one hundred thirty million, forty-four thousand, five hundred thirteen".

Divisors: 1 17 289 107716417 1831179089 31130044513