Base | Representation |
---|---|
bin | 1110001010000000100100… |
… | …10111101010101000000101 |
3 | 11002020000120100000022220212 |
4 | 13011000102113222220011 |
5 | 13040014203133431310 |
6 | 150113010351205205 |
7 | 6362041101606410 |
oct | 705002227525005 |
9 | 132200510008825 |
10 | 31130231155205 |
11 | 9a12290a18436 |
12 | 35a92b7516805 |
13 | 144a750454630 |
14 | 7989d5870b77 |
15 | 38eb7e814205 |
hex | 1c50125eaa05 |
31130231155205 has 256 divisors, whose sum is σ = 50039119872000. Its totient is φ = 18046253481984.
The previous prime is 31130231155189. The next prime is 31130231155207. The reversal of 31130231155205 is 50255113203113.
It is not a de Polignac number, because 31130231155205 - 24 = 31130231155189 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31130231155207) by changing a digit.
It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 9267706316 + ... + 9267709674.
It is an arithmetic number, because the mean of its divisors is an integer number (195465312000).
Almost surely, 231130231155205 is an apocalyptic number.
31130231155205 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
31130231155205 is a deficient number, since it is larger than the sum of its proper divisors (18908888716795).
31130231155205 is a wasteful number, since it uses less digits than its factorization.
31130231155205 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3748.
The product of its (nonzero) digits is 13500, while the sum is 32.
Adding to 31130231155205 its reverse (50255113203113), we get a palindrome (81385344358318).
The spelling of 31130231155205 in words is "thirty-one trillion, one hundred thirty billion, two hundred thirty-one million, one hundred fifty-five thousand, two hundred five".
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