Base | Representation |
---|---|
bin | 1001000011110111001… |
… | …01010010111111100000 |
3 | 1002202112210121101012210 |
4 | 10201323211102333200 |
5 | 20100031110120000 |
6 | 355003031322120 |
7 | 31330402003131 |
oct | 4417345227740 |
9 | 1082483541183 |
10 | 311311020000 |
11 | 110031a56012 |
12 | 50401520340 |
13 | 23483311c56 |
14 | 110d3453c88 |
15 | 81706d7350 |
hex | 487b952fe0 |
311311020000 has 240 divisors, whose sum is σ = 1028983519872. Its totient is φ = 82380480000.
The previous prime is 311311019993. The next prime is 311311020001. The reversal of 311311020000 is 20113113.
311311020000 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (240).
It is a super-3 number, since 3×3113110200003 (a number of 35 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311311020001) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 7840197 + ... + 7879803.
Almost surely, 2311311020000 is an apocalyptic number.
311311020000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 311311020000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (514491759936).
311311020000 is an abundant number, since it is smaller than the sum of its proper divisors (717672499872).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
311311020000 is a wasteful number, since it uses less digits than its factorization.
311311020000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39771 (or 39748 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 12.
Adding to 311311020000 its reverse (20113113), we get a palindrome (311331133113).
The spelling of 311311020000 in words is "three hundred eleven billion, three hundred eleven million, twenty thousand".
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