Base | Representation |
---|---|
bin | 1001000011110111010… |
… | …01110110010001111101 |
3 | 1002202112212211222212022 |
4 | 10201323221312101331 |
5 | 20100031411304432 |
6 | 355003113045525 |
7 | 31330415102453 |
oct | 4417351662175 |
9 | 1082485758768 |
10 | 311312213117 |
11 | 1100326a0464 |
12 | 504019b68a5 |
13 | 2348363c039 |
14 | 110d36849d3 |
15 | 8170870b12 |
hex | 487ba7647d |
311312213117 has 2 divisors, whose sum is σ = 311312213118. Its totient is φ = 311312213116.
The previous prime is 311312213027. The next prime is 311312213119. The reversal of 311312213117 is 711312213113.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 165318680836 + 145993532281 = 406594^2 + 382091^2 .
It is a cyclic number.
It is not a de Polignac number, because 311312213117 - 210 = 311312212093 is a prime.
Together with 311312213119, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (311312213119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 155656106558 + 155656106559.
It is an arithmetic number, because the mean of its divisors is an integer number (155656106559).
Almost surely, 2311312213117 is an apocalyptic number.
It is an amenable number.
311312213117 is a deficient number, since it is larger than the sum of its proper divisors (1).
311312213117 is an equidigital number, since it uses as much as digits as its factorization.
311312213117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 756, while the sum is 26.
The spelling of 311312213117 in words is "three hundred eleven billion, three hundred twelve million, two hundred thirteen thousand, one hundred seventeen".
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