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3113130112103 = 11283011828373
BaseRepresentation
bin101101010011010101000…
…000111011010001100111
3102000121112101112102102002
4231103111000323101213
5402001142302041403
610342052514235515
7440626160225564
oct55232500732147
912017471472362
103113130112103
11aa02a88753a0
12423418b85b9b
1319774a668b3b
14aa967ab186b
1555ea6532188
hex2d4d503b467

3113130112103 has 4 divisors (see below), whose sum is σ = 3396141940488. Its totient is φ = 2830118283720.

The previous prime is 3113130112051. The next prime is 3113130112171. The reversal of 3113130112103 is 3012110313113.

3113130112103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3113130112103 - 210 = 3113130111079 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3113130111103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 141505914176 + ... + 141505914197.

It is an arithmetic number, because the mean of its divisors is an integer number (849035485122).

Almost surely, 23113130112103 is an apocalyptic number.

3113130112103 is a deficient number, since it is larger than the sum of its proper divisors (283011828385).

3113130112103 is a wasteful number, since it uses less digits than its factorization.

3113130112103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 283011828384.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 3113130112103 its reverse (3012110313113), we get a palindrome (6125240425216).

The spelling of 3113130112103 in words is "three trillion, one hundred thirteen billion, one hundred thirty million, one hundred twelve thousand, one hundred three".

Divisors: 1 11 283011828373 3113130112103