Base | Representation |
---|---|
bin | 10010100011100… |
… | …101111000110011 |
3 | 210200210200220122 |
4 | 102203211320303 |
5 | 1114144220430 |
6 | 50520400455 |
7 | 10500114551 |
oct | 2243457063 |
9 | 720720818 |
10 | 311320115 |
11 | 14a806457 |
12 | 8831612b |
13 | 4c6624b2 |
14 | 2d4bcbd1 |
15 | 1c4e7ee5 |
hex | 128e5e33 |
311320115 has 4 divisors (see below), whose sum is σ = 373584144. Its totient is φ = 249056088.
The previous prime is 311320103. The next prime is 311320159. The reversal of 311320115 is 511023113.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511023113 = 79 ⋅6468647.
It is a cyclic number.
It is not a de Polignac number, because 311320115 - 214 = 311303731 is a prime.
It is a super-2 number, since 2×3113201152 = 193840428007226450, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 311320093 and 311320102.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31132007 + ... + 31132016.
It is an arithmetic number, because the mean of its divisors is an integer number (93396036).
Almost surely, 2311320115 is an apocalyptic number.
311320115 is a deficient number, since it is larger than the sum of its proper divisors (62264029).
311320115 is an equidigital number, since it uses as much as digits as its factorization.
311320115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62264028.
The product of its (nonzero) digits is 90, while the sum is 17.
The square root of 311320115 is about 17644.2657824008. The cubic root of 311320115 is about 677.7492735233.
Adding to 311320115 its reverse (511023113), we get a palindrome (822343228).
The spelling of 311320115 in words is "three hundred eleven million, three hundred twenty thousand, one hundred fifteen".
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