3113210021 has 4 divisors (see below), whose sum is σ = 3277063200. Its totient is φ = 2949356844.

The previous prime is 3113209997. The next prime is 3113210027. The reversal of 3113210021 is 1200123113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1200123113 = 7 ⋅171446159.

It is a cyclic number.

It is not a de Polignac number, because 3113210021 - 2¹⁴ = 3113193637 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3113209978 and 3113210005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3113210027) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81926561 + ... + 81926598.

It is an arithmetic number, because the mean of its divisors is an integer number (819265800).

Almost surely, 2^3113210021 is an apocalyptic number.

It is an amenable number.

3113210021 is a deficient number, since it is larger than the sum of its proper divisors (163853179).

3113210021 is a wasteful number, since it uses less digits than its factorization.

3113210021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163853178.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 3113210021 is about 55796.1470085525. The cubic root of 3113210021 is about 1460.1679329256.

Adding to 3113210021 its reverse (1200123113), we get a palindrome (4313333134).

The spelling of 3113210021 in words is "three billion, one hundred thirteen million, two hundred ten thousand, twenty-one".