Search a number
-
+
3113212004303 = 3139946364231
BaseRepresentation
bin101101010011011001111…
…001010100011111001111
3102000121202002121222101112
4231103121321110133033
5402001324233114203
610342105001402235
7440631203262422
oct55233171243717
912017662558345
103113212004303
11aa03400191a5
1242344049937b
1319776160c56b
14aa97490b9b9
1555ead80b6d8
hex2d4d9e547cf

3113212004303 has 4 divisors (see below), whose sum is σ = 3123158368848. Its totient is φ = 3103265639760.

The previous prime is 3113212004269. The next prime is 3113212004311. The reversal of 3113212004303 is 3034002123113.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3113212004303 - 28 = 3113212004047 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3113212004003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4973181803 + ... + 4973182428.

It is an arithmetic number, because the mean of its divisors is an integer number (780789592212).

Almost surely, 23113212004303 is an apocalyptic number.

3113212004303 is a deficient number, since it is larger than the sum of its proper divisors (9946364545).

3113212004303 is an equidigital number, since it uses as much as digits as its factorization.

3113212004303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9946364544.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 3113212004303 its reverse (3034002123113), we get a palindrome (6147214127416).

The spelling of 3113212004303 in words is "three trillion, one hundred thirteen billion, two hundred twelve million, four thousand, three hundred three".

Divisors: 1 313 9946364231 3113212004303