Base | Representation |
---|---|
bin | 101101010011011010000… |
… | …001000001100110100101 |
3 | 102000121202020102121000212 |
4 | 231103122001001212211 |
5 | 402001330242232401 |
6 | 10342105112545205 |
7 | 440631226404146 |
oct | 55233201014645 |
9 | 12017666377025 |
10 | 3113214024101 |
11 | aa0341178755 |
12 | 4234410b2205 |
13 | 197761b689cc |
14 | aa974cb5acd |
15 | 55eadaa9dbb |
hex | 2d4da0419a5 |
3113214024101 has 2 divisors, whose sum is σ = 3113214024102. Its totient is φ = 3113214024100.
The previous prime is 3113214024073. The next prime is 3113214024143. The reversal of 3113214024101 is 1014204123113.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1972592160100 + 1140621864001 = 1404490^2 + 1067999^2 .
It is an emirp because it is prime and its reverse (1014204123113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3113214024101 - 222 = 3113209829797 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3113214024001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556607012050 + 1556607012051.
It is an arithmetic number, because the mean of its divisors is an integer number (1556607012051).
Almost surely, 23113214024101 is an apocalyptic number.
It is an amenable number.
3113214024101 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113214024101 is an equidigital number, since it uses as much as digits as its factorization.
3113214024101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 3113214024101 its reverse (1014204123113), we get a palindrome (4127418147214).
The spelling of 3113214024101 in words is "three trillion, one hundred thirteen billion, two hundred fourteen million, twenty-four thousand, one hundred one".
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