Base | Representation |
---|---|
bin | 101101010011011111001… |
… | …101111111101100111111 |
3 | 102000121222022200012010222 |
4 | 231103133031333230333 |
5 | 402002020113412041 |
6 | 10342121511451555 |
7 | 440633336334605 |
oct | 55233715775477 |
9 | 12017868605128 |
10 | 3113301310271 |
11 | aa0386476089 |
12 | 423466386bbb |
13 | 197776c7a629 |
14 | aa982717875 |
15 | 55eb659c74b |
hex | 2d4df37fb3f |
3113301310271 has 2 divisors, whose sum is σ = 3113301310272. Its totient is φ = 3113301310270.
The previous prime is 3113301310261. The next prime is 3113301310381. The reversal of 3113301310271 is 1720131033113.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3113301310271 - 230 = 3112227568447 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3113301310271.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3113301310201) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1556650655135 + 1556650655136.
It is an arithmetic number, because the mean of its divisors is an integer number (1556650655136).
Almost surely, 23113301310271 is an apocalyptic number.
3113301310271 is a deficient number, since it is larger than the sum of its proper divisors (1).
3113301310271 is an equidigital number, since it uses as much as digits as its factorization.
3113301310271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 26.
Adding to 3113301310271 its reverse (1720131033113), we get a palindrome (4833432343384).
The spelling of 3113301310271 in words is "three trillion, one hundred thirteen billion, three hundred one million, three hundred ten thousand, two hundred seventy-one".
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