Base | Representation |
---|---|
bin | 1001000011111011000… |
… | …11010000000011001101 |
3 | 1002202122002201212112010 |
4 | 10201331203100003031 |
5 | 20100113033204333 |
6 | 355010211131433 |
7 | 31331252441604 |
oct | 4417543200315 |
9 | 1082562655463 |
10 | 311344038093 |
11 | 110049657aa0 |
12 | 504105a3b79 |
13 | 2348a10289a |
14 | 110d79aaa3b |
15 | 817355a563 |
hex | 487d8d00cd |
311344038093 has 16 divisors (see below), whose sum is σ = 456429920256. Its totient is φ = 187207579440.
The previous prime is 311344038037. The next prime is 311344038127. The reversal of 311344038093 is 390830443113.
It is not a de Polignac number, because 311344038093 - 225 = 311310483661 is a prime.
It is a super-2 number, since 2×3113440380932 (a number of 24 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (311344038293) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 37140171 + ... + 37148552.
It is an arithmetic number, because the mean of its divisors is an integer number (28526870016).
Almost surely, 2311344038093 is an apocalyptic number.
311344038093 is a gapful number since it is divisible by the number (33) formed by its first and last digit.
It is an amenable number.
311344038093 is a deficient number, since it is larger than the sum of its proper divisors (145085882163).
311344038093 is a wasteful number, since it uses less digits than its factorization.
311344038093 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74288864.
The product of its (nonzero) digits is 93312, while the sum is 39.
The spelling of 311344038093 in words is "three hundred eleven billion, three hundred forty-four million, thirty-eight thousand, ninety-three".
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