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31140040013 = 55411561983
BaseRepresentation
bin11101000000000101…
…110100110101001101
32222101012110221021022
4131000011310311031
51002233322240023
622145555043525
72151451654445
oct350005646515
988335427238
1031140040013
111222a816a65
1260508a05a5
132c236248a4
141715a0b125
15c23c6d7c8
hex740174d4d

31140040013 has 4 divisors (see below), whose sum is σ = 31140657408. Its totient is φ = 31139422620.

The previous prime is 31140039979. The next prime is 31140040031. The reversal of 31140040013 is 31004004113.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 31140040013 - 216 = 31139974477 is a prime.

It is a super-2 number, since 2×311400400132 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 31140039973 and 31140040000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (31140040033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 225581 + ... + 336402.

It is an arithmetic number, because the mean of its divisors is an integer number (7785164352).

Almost surely, 231140040013 is an apocalyptic number.

It is an amenable number.

31140040013 is a deficient number, since it is larger than the sum of its proper divisors (617395).

31140040013 is an equidigital number, since it uses as much as digits as its factorization.

31140040013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 617394.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 31140040013 its reverse (31004004113), we get a palindrome (62144044126).

The spelling of 31140040013 in words is "thirty-one billion, one hundred forty million, forty thousand, thirteen".

Divisors: 1 55411 561983 31140040013