Base | Representation |
---|---|
bin | 101101010100001001101… |
… | …001101001000001110111 |
3 | 102000200210221012221221212 |
4 | 231110021221221001313 |
5 | 402004444334404003 |
6 | 10342320302032035 |
7 | 440660102320412 |
oct | 55241151510167 |
9 | 12020727187855 |
10 | 3114013200503 |
11 | aa07112a6817 |
12 | 42362487861b |
13 | 19785b5c0a5a |
14 | aaa0d0a8b79 |
15 | 56008d1cdd8 |
hex | 2d509a69077 |
3114013200503 has 2 divisors, whose sum is σ = 3114013200504. Its totient is φ = 3114013200502.
The previous prime is 3114013200439. The next prime is 3114013200511. The reversal of 3114013200503 is 3050023104113.
It is a strong prime.
It is an emirp because it is prime and its reverse (3050023104113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3114013200503 - 26 = 3114013200439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3114013200593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557006600251 + 1557006600252.
It is an arithmetic number, because the mean of its divisors is an integer number (1557006600252).
Almost surely, 23114013200503 is an apocalyptic number.
3114013200503 is a deficient number, since it is larger than the sum of its proper divisors (1).
3114013200503 is an equidigital number, since it uses as much as digits as its factorization.
3114013200503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 3114013200503 its reverse (3050023104113), we get a palindrome (6164036304616).
The spelling of 3114013200503 in words is "three trillion, one hundred fourteen billion, thirteen million, two hundred thousand, five hundred three".
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