Base | Representation |
---|---|
bin | 101101010100001011111… |
… | …110100010010100111011 |
3 | 102000200220122122222210122 |
4 | 231110023332202110323 |
5 | 402010034332420012 |
6 | 10342324214403455 |
7 | 440661055144346 |
oct | 55241376422473 |
9 | 12020818588718 |
10 | 3114052232507 |
11 | aa0731336077 |
12 | 42363596058b |
13 | 197866708b08 |
14 | aaa1434945d |
15 | 5600c47ce72 |
hex | 2d50bfa253b |
3114052232507 has 2 divisors, whose sum is σ = 3114052232508. Its totient is φ = 3114052232506.
The previous prime is 3114052232483. The next prime is 3114052232509. The reversal of 3114052232507 is 7052322504113.
It is a strong prime.
It is an emirp because it is prime and its reverse (7052322504113) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3114052232507 - 28 = 3114052232251 is a prime.
Together with 3114052232509, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (3114052232509) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557026116253 + 1557026116254.
It is an arithmetic number, because the mean of its divisors is an integer number (1557026116254).
Almost surely, 23114052232507 is an apocalyptic number.
3114052232507 is a deficient number, since it is larger than the sum of its proper divisors (1).
3114052232507 is an equidigital number, since it uses as much as digits as its factorization.
3114052232507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50400, while the sum is 35.
The spelling of 3114052232507 in words is "three trillion, one hundred fourteen billion, fifty-two million, two hundred thirty-two thousand, five hundred seven".
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