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3114052232507 is a prime number
BaseRepresentation
bin101101010100001011111…
…110100010010100111011
3102000200220122122222210122
4231110023332202110323
5402010034332420012
610342324214403455
7440661055144346
oct55241376422473
912020818588718
103114052232507
11aa0731336077
1242363596058b
13197866708b08
14aaa1434945d
155600c47ce72
hex2d50bfa253b

3114052232507 has 2 divisors, whose sum is σ = 3114052232508. Its totient is φ = 3114052232506.

The previous prime is 3114052232483. The next prime is 3114052232509. The reversal of 3114052232507 is 7052322504113.

It is a strong prime.

It is an emirp because it is prime and its reverse (7052322504113) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3114052232507 - 28 = 3114052232251 is a prime.

Together with 3114052232509, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3114052232509) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1557026116253 + 1557026116254.

It is an arithmetic number, because the mean of its divisors is an integer number (1557026116254).

Almost surely, 23114052232507 is an apocalyptic number.

3114052232507 is a deficient number, since it is larger than the sum of its proper divisors (1).

3114052232507 is an equidigital number, since it uses as much as digits as its factorization.

3114052232507 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50400, while the sum is 35.

The spelling of 3114052232507 in words is "three trillion, one hundred fourteen billion, fifty-two million, two hundred thirty-two thousand, five hundred seven".