Base | Representation |
---|---|
bin | 101101010100001101011… |
… | …011010100010011001011 |
3 | 102000200222100102200020002 |
4 | 231110031123110103023 |
5 | 402010112044220233 |
6 | 10342330443553215 |
7 | 440661501653651 |
oct | 55241533242313 |
9 | 12020870380202 |
10 | 3114076554443 |
11 | aa0744038548 |
12 | 423641b2b80b |
13 | 19786b7734aa |
14 | aaa1767add1 |
15 | 5600e6846e8 |
hex | 2d50d6d44cb |
3114076554443 has 4 divisors (see below), whose sum is σ = 3115040966640. Its totient is φ = 3113112142248.
The previous prime is 3114076554419. The next prime is 3114076554487. The reversal of 3114076554443 is 3444556704113.
It is a happy number.
3114076554443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3114076554443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3114076550443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 482201255 + ... + 482207712.
It is an arithmetic number, because the mean of its divisors is an integer number (778760241660).
Almost surely, 23114076554443 is an apocalyptic number.
3114076554443 is a deficient number, since it is larger than the sum of its proper divisors (964412197).
3114076554443 is an equidigital number, since it uses as much as digits as its factorization.
3114076554443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 964412196.
The product of its (nonzero) digits is 2419200, while the sum is 47.
The spelling of 3114076554443 in words is "three trillion, one hundred fourteen billion, seventy-six million, five hundred fifty-four thousand, four hundred forty-three".
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